find 𝑖𝑛 𝑅 the 𝑆.𝑆. 𝑜𝑓 each 𝑜𝑓 the following equation:𝑋2-8𝑋+15=0

Sure, here are the steps to find the solution set of the equation x² - 8x + 15 = 0:

Step 1: Identify the coefficients of the quadratic equation. In this case, a = 1 (coefficient of x²), b = -8 (coefficient of x), and c = 15 (constant term).

Step 2: Use the quadratic formula, which is x = [-b ± sqrt(b² - 4ac)] / (2a).

Step 3: Substitute the values of a, b, and c into the formula. This gives us x = [8 ± sqrt((-8)² - 4115)] / (2*1).

Step 4: Simplify the expression under the square root. This gives us x = [8 ± sqrt(64 - 60)] / 2.

Step 5: Further simplify the expression. This gives us x = [8 ± sqrt(4)] / 2.

Step 6: Calculate the square root. This gives us x = [8 ± 2] / 2.

Step 7: Finally, solve for x. This gives us x = 10/2 or x = 6/2.

So, the solution set of the equation x² - 8x + 15 = 0 is {3, 5}.