In an ac circuit, V and I are given by    V = 100 sin (100 t) volts, I = 100 sin  mA.The power dissipated in circuit is :104 watt    10 watt    2.5 watt    5 watt

To find the power dissipated in the circuit, we can use the formula P = V * I * cos(θ), where P is the power, V is the voltage, I is the current, and θ is the phase angle between the voltage and current.

Given that V = 100 sin (100t) volts and I = 100 sin mA, we can see that the voltage and current are both sinusoidal functions.

To calculate the power, we need to find the instantaneous values of voltage and current at any given time. Since both V and I are given as sinusoidal functions, we can use the trigonometric identity sin(a) * sin(b) = (1/2) * [cos(a - b) - cos(a + b)] to find the product of V and I.

Using this identity, we have:

V * I = (100 sin (100t)) * (100 sin mA) = (1/2) * [cos(100t - mA) - cos(100t + mA)]

Now, we can calculate the power dissipated in the circuit by multiplying V * I by the power factor, which is the cosine of the phase angle between V and I.

Since the power factor is not given in the question, we cannot determine the exact power dissipated in the circuit. Therefore, none of the provided options (104 watt, 10 watt, 2.5 watt, 5 watt) can be selected as the correct answer.