A boy starts jumping from the origin point. He covers a horizontal distance of 1.2 m in a single jump. If he jumps ten times in the forward direction and three times in a backward direction, the final position of the boy will be
Question
A boy starts jumping from the origin point. He covers a horizontal distance of 1.2 m in a single jump. If he jumps ten times in the forward direction and three times in a backward direction, the final position of the boy will be
Solution
To find the final position of the boy, we need to calculate the total distance covered in the forward direction and the total distance covered in the backward direction.
Step 1: Calculate the total distance covered in the forward direction. The boy jumps 10 times in the forward direction, and each jump covers a distance of 1.2 m. So, the total distance covered in the forward direction is 10 jumps * 1.2 m/jump = 12 m.
Step 2: Calculate the total distance covered in the backward direction. The boy jumps 3 times in the backward direction, and each jump covers a distance of 1.2 m. So, the total distance covered in the backward direction is 3 jumps * 1.2 m/jump = 3.6 m.
Step 3: Calculate the final position of the boy. The final position of the boy is the total distance covered in the forward direction minus the total distance covered in the backward direction. So, the final position of the boy is 12 m - 3.6 m = 8.4 m.
So, the final position of the boy will be 8.4 m in the forward direction from the origin point.
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