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he compound carbon suboxide, C3O2, is a gas at room temperature. Use the data supplied to calculate the heat of formation of carbon suboxide.Data:2CO(g) + C(s) → C3O2(g), ΔH° = 127.3 kJ/mol and ΔH°f of CO(g) = -110.5 kJ/mol)

Question

he compound carbon suboxide, C3O2, is a gas at room temperature. Use the data supplied to calculate the heat of formation of carbon suboxide.Data:2CO(g) + C(s) → C3O2(g), ΔH° = 127.3 kJ/mol and ΔH°f of CO(g) = -110.5 kJ/mol)

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Solution

To calculate the heat of formation (ΔH°f) of carbon suboxide (C3O2), we can use the given reaction and the heat of formation of carbon monoxide (CO).

The given reaction is: 2CO(g) + C(s) → C3O2(g), ΔH° = 127.3 kJ/mol

The heat of formation of CO(g) is given as -110.5 kJ/mol.

The heat of formation of a compound is the change in enthalpy that accompanies the formation of one mole of the compound from its elements in their standard states.

For the given reaction, the heat of formation of C3O2 can be calculated using the following equation:

ΔH°f [C3O2(g)] = ΔH° [reaction] - 2*ΔH°f [CO(g)]

Substituting the given values into the equation:

ΔH°f [C3O2(g)] = 127.3 kJ/mol - 2*(-110.5 kJ/mol)

ΔH°f [C3O2(g)] = 127.3 kJ/mol + 221 kJ/mol

ΔH°f [C3O2(g)] = 348.3 kJ/mol

So, the heat of formation of carbon suboxide is 348.3 kJ/mol.

This problem has been solved

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