The correct answer is 1[].

Here's why:

The `collections.defaultdict` function is a dictionary subclass that calls a factory function to supply missing values. In this case, the factory function is `list`, which means that if a key is not currently in the dictionary, the `defaultdict` will automatically assign an empty list to that key.

So, when you try to access `temp[1]`, even though the key `1` has not been assigned a value, `defaultdict` automatically assigns it the value `[]` (an empty list). Therefore, the output of the code is `[]`.

Question

The correct answer is 1[].

Here's why:

The `collections.defaultdict` function is a dictionary subclass that calls a factory function to supply missing values. In this case, the factory function is `list`, which means that if a key is not currently in the dictionary, the `defaultdict` will automatically assign an empty list to that key.

So, when you try to access `temp[1]`, even though the key `1` has not been assigned a value, `defaultdict` automatically assigns it the value `[]` (an empty list). Therefore, the output of the code is `[]`.

Knowee AI · Accepted Answer

The correct answer is 1[].

Here's why:

The `collections.defaultdict` function is a dictionary subclass that calls a factory function to supply missing values. In this case, the factory function is `list`, which means that if a key is not currently in the dictionary, the `defaultdict` will automatically assign an empty list to that key.

So, when you try to access `temp[1]`, even though the key `1` has not been assigned a value, `defaultdict` automatically assigns it the value `[]` (an empty list). Therefore, the output of the code is `[]`.

What will be the output of the following code?import collectionstemp = dict()temp = collections.defaultdict(list) print(temp[1])Options: Pick one correct answer from below1[]An exception is thrown" "

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