To solve this problem, we need to use the formula for heat transfer:

q = mcΔT

where:
q = heat energy (in Joules)
m = mass (in grams)
c = specific heat capacity (in J/g°C)
ΔT = change in temperature (in °C)

First, we need to convert the heat energy from kJ to J because the specific heat capacity is given in J/g°C.

1.9 kJ = 1.9 * 1000 = 1900 J

We know that:
q = 1900 J
m = 96 g
c = 0.897 J/g°C

We need to find ΔT, so we rearrange the formula to solve for ΔT:

ΔT = q / (mc)

Substituting the known values:

ΔT = 1900 J / (96 g * 0.897 J/g°C) = 22.2°C

The final temperature would be the initial temperature plus the change in temperature:

Final temperature = Initial temperature + ΔT
Final temperature = 113°C + 22.2°C = 135.2°C

So, the new temperature of the aluminum would be approximately 135°C. Therefore, the answer is D. 135°C.

Question

To solve this problem, we need to use the formula for heat transfer:

q = mcΔT

where:
q = heat energy (in Joules)
m = mass (in grams)
c = specific heat capacity (in J/g°C)
ΔT = change in temperature (in °C)

First, we need to convert the heat energy from kJ to J because the specific heat capacity is given in J/g°C.

1.9 kJ = 1.9 * 1000 = 1900 J

We know that:
q = 1900 J
m = 96 g
c = 0.897 J/g°C

We need to find ΔT, so we rearrange the formula to solve for ΔT:

ΔT = q / (mc)

Substituting the known values:

ΔT = 1900 J / (96 g * 0.897 J/g°C) = 22.2°C

The final temperature would be the initial temperature plus the change in temperature:

Final temperature = Initial temperature + ΔT
Final temperature = 113°C + 22.2°C = 135.2°C

So, the new temperature of the aluminum would be approximately 135°C. Therefore, the answer is D. 135°C.

Knowee AI · Accepted Answer