The list comprehension equivalent for `list(map(lambda x:x**-1, [1, 2, 3]))` is `[x**-1 for x in [1, 2, 3]]`.

Here's the step by step breakdown:

1. `list(map(lambda x:x**-1, [1, 2, 3]))` is using the `map` function to apply a lambda function to each element in the list `[1, 2, 3]`. The lambda function is `lambda x:x**-1`, which takes an input `x` and returns `x**-1` (which is the same as 1 divided by `x`).

2. In list comprehension, we can do the same thing in a more concise way. The format is `[expression for item in list]`.

3. So, we take the expression from the lambda function, which is `x**-1`, and put it at the beginning of the list comprehension.

4. Then we follow it with `for x in [1, 2, 3]`, which means "for each element `x` in the list `[1, 2, 3]`".

5. Putting it all together, we get `[x**-1 for x in [1, 2, 3]]`. This will return the same result as the original `map` function.

Question

The list comprehension equivalent for `list(map(lambda x:x**-1, [1, 2, 3]))` is `[x**-1 for x in [1, 2, 3]]`.

Here's the step by step breakdown:

1. `list(map(lambda x:x**-1, [1, 2, 3]))` is using the `map` function to apply a lambda function to each element in the list `[1, 2, 3]`. The lambda function is `lambda x:x**-1`, which takes an input `x` and returns `x**-1` (which is the same as 1 divided by `x`).

2. In list comprehension, we can do the same thing in a more concise way. The format is `[expression for item in list]`.

3. So, we take the expression from the lambda function, which is `x**-1`, and put it at the beginning of the list comprehension.

4. Then we follow it with `for x in [1, 2, 3]`, which means "for each element `x` in the list `[1, 2, 3]`".

5. Putting it all together, we get `[x**-1 for x in [1, 2, 3]]`. This will return the same result as the original `map` function.

Knowee AI · Accepted Answer

The list comprehension equivalent for `list(map(lambda x:x**-1, [1, 2, 3]))` is `[x**-1 for x in [1, 2, 3]]`.

Here's the step by step breakdown:

1. `list(map(lambda x:x**-1, [1, 2, 3]))` is using the `map` function to apply a lambda function to each element in the list `[1, 2, 3]`. The lambda function is `lambda x:x**-1`, which takes an input `x` and returns `x**-1` (which is the same as 1 divided by `x`).

2. In list comprehension, we can do the same thing in a more concise way. The format is `[expression for item in list]`.

3. So, we take the expression from the lambda function, which is `x**-1`, and put it at the beginning of the list comprehension.

4. Then we follow it with `for x in [1, 2, 3]`, which means "for each element `x` in the list `[1, 2, 3]`".

5. Putting it all together, we get `[x**-1 for x in [1, 2, 3]]`. This will return the same result as the original `map` function.

What is the list comprehension equivalent for:list(map(lambda x:x**-1, [1, 2, 3]))?

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