A ball of mass 0.100 kg moving with speed of 2.34 m/s hits a wall and bounces back with the same speed in the opposite direction. What is the change in the ball's kinetic energy?
Question
A ball of mass 0.100 kg moving with speed of 2.34 m/s hits a wall and bounces back with the same speed in the opposite direction. What is the change in the ball's kinetic energy?
Solution
The kinetic energy of an object is given by the formula KE = 1/2 * m * v^2, where m is the mass of the object and v is its velocity.
Before the ball hits the wall, its kinetic energy is KE_initial = 1/2 * 0.100 kg * (2.34 m/s)^2 = 0.27458 J.
After the ball bounces back, its speed is the same but its direction is opposite. However, kinetic energy is a scalar quantity, not a vector, so it doesn't depend on the direction of the velocity. Therefore, the kinetic energy of the ball after it bounces back is the same as before it hit the wall, KE_final = 0.27458 J.
The change in kinetic energy is given by ΔKE = KE_final - KE_initial = 0.27458 J - 0.27458 J = 0 J.
So, the change in the ball's kinetic energy is 0 J.
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