The increasing order of complexity of the functions f1, f2, f3, and f4 is as follows:

f3(n) = nLogn
f2(n) = n^(3/2)
f4(n) = n^(Logn)
f1(n) = 2^n

Here's why:

1. f3(n) = nLogn: This is a linearithmic function. It grows faster than a linear function but slower than a polynomial function.

2. f2(n) = n^(3/2): This is a polynomial function. It grows faster than a linear and linearithmic function but slower than an exponential function.

3. f4(n) = n^(Logn): This is a super-polynomial function. It grows faster than a polynomial function but slower than an exponential function.

4. f1(n) = 2^n: This is an exponential function. It grows the fastest among the four functions.

Question

The increasing order of complexity of the functions f1, f2, f3, and f4 is as follows:

f3(n) = nLogn
f2(n) = n^(3/2)
f4(n) = n^(Logn)
f1(n) = 2^n

Here's why:

1. f3(n) = nLogn: This is a linearithmic function. It grows faster than a linear function but slower than a polynomial function.

2. f2(n) = n^(3/2): This is a polynomial function. It grows faster than a linear and linearithmic function but slower than an exponential function.

3. f4(n) = n^(Logn): This is a super-polynomial function. It grows faster than a polynomial function but slower than an exponential function.

4. f1(n) = 2^n: This is an exponential function. It grows the fastest among the four functions.

Knowee AI · Accepted Answer

The increasing order of complexity of the functions f1, f2, f3, and f4 is as follows:

f3(n) = nLogn
f2(n) = n^(3/2)
f4(n) = n^(Logn)
f1(n) = 2^n

Here's why:

1. f3(n) = nLogn: This is a linearithmic function. It grows faster than a linear function but slower than a polynomial function.

2. f2(n) = n^(3/2): This is a polynomial function. It grows faster than a linear and linearithmic function but slower than an exponential function.

3. f4(n) = n^(Logn): This is a super-polynomial function. It grows faster than a polynomial function but slower than an exponential function.

4. f1(n) = 2^n: This is an exponential function. It grows the fastest among the four functions.

Which of the given options provides the increasing order of complexity of functions f1, f2, f3 and f4:f1(n) = 2^nf2(n) = n^(3/2)f3(n) = nLognf4(n) = n^(Logn)