Two bodies of masses M and 4M are moving with equal kinetic energies. What is the ratio of their linear momenta? 2:11:41:21:6
Question
Two bodies of masses M and 4M are moving with equal kinetic energies. What is the ratio of their linear momenta? 2:11:41:21:6
Solution
The kinetic energy of an object is given by the equation KE = 1/2 mv^2, where m is the mass and v is the velocity of the object.
Given that the two bodies have equal kinetic energies, we can set their kinetic energy equations equal to each other:
1/2 Mv1^2 = 1/2 4Mv2^2
Solving for v1/v2 gives us:
v1/v2 = sqrt(4M/M) = 2
The linear momentum of an object is given by the equation p = mv.
So, the ratio of their linear momenta is:
p1/p2 = Mv1/(4Mv2) = (1/4) * (v1/v2) = (1/4) * 2 = 1/2
So, the ratio of their linear momenta is 1:2.
Similar Questions
Two particles of masses m1 and m2 have equal linear momenta. The ratio of their kinetic energy
Two bodies of masses m1 & m2 have the same linear momentum. What is the ratio of their kinetic energies?None of these
Two bodies A and B having masses in the ratio of 3 : 1 possess the same kinetic energy. The ratio of linear momentum of B to A is :
A body of mass m1 moving with uniform velocity of 40 m/s collides with another mass m2 at rest and then the two bodies begins to move together with a uniform velocity of 30 m/s. The ratio of their masses (m1/m2) is :-34
Two bodies m1 and m2 (m1 > m2) have the same kinetic energy. Then their momentum p1 and p2
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.