In a certain application, a Half wave controlled rectifier is fed from a voltage vs(t)=320sin(100pi (t)) as shown in figure with an inductive load and a free-wheeling diode. The thyristor firing angle is 90 degrees. Therefore the average output voltage in Volts across the load is: Select one:a. 41.12b. 50.93c. 106.67d. 88.86
Question
In a certain application, a Half wave controlled rectifier is fed from a voltage vs(t)=320sin(100pi (t)) as shown in figure with an inductive load and a free-wheeling diode. The thyristor firing angle is 90 degrees. Therefore the average output voltage in Volts across the load is: Select one:a. 41.12b. 50.93c. 106.67d. 88.86
Solution
The average output voltage (Vavg) for a half-wave controlled rectifier with a firing angle (α) can be calculated using the following formula:
Vavg = (2Vm/π) * (1 + cosα)
Where:
- Vm is the peak voltage, which is the maximum voltage of the input sinusoidal signal. In this case, Vm = 320V.
- α is the firing angle of the thyristor. In this case, α = 90 degrees.
Substituting the given values into the formula, we get:
Vavg = (2*320/π) * (1 + cos90) = (640/π) * (1 + 0) = 640/π = 203.64V
However, this is the average voltage for a full wave rectifier. Since we are dealing with a half wave rectifier, we need to divide this result by 2:
Vavg = 203.64/2 = 101.82V
This value is not listed in the provided options. There might be a mistake in the question or the provided options. Please check the question and the options again.
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