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319.3 grams of Na2O2 = ____________________________ molecules of Na2O2

Question

319.3 grams of Na2O2 = ____________________________ molecules of Na2O2

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Solution

To find the number of molecules in 319.3 grams of Na2O2, you need to follow these steps:

  1. First, find the molar mass of Na2O2. The atomic mass of Sodium (Na) is approximately 23 grams/mole and Oxygen (O) is approximately 16 grams/mole. So, the molar mass of Na2O2 = 2(23) + 2(16) = 78 grams/mole.

  2. Next, find the number of moles in 319.3 grams of Na2O2. To do this, divide the mass of Na2O2 by its molar mass. So, 319.3 grams ÷ 78 grams/mole = approximately 4.09 moles.

  3. Finally, find the number of molecules. Use Avogadro's number, which states that there are approximately 6.022 x 10^23 molecules in one mole. So, 4.09 moles x 6.022 x 10^23 molecules/mole = approximately 2.46 x 10^24 molecules.

So, 319.3 grams of Na2O2 is approximately equal to 2.46 x 10^24 molecules of Na2O2.

This problem has been solved

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