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What is the projection of vector BA onto BC?

Question

What is the projection of vector BA onto BC?

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Solution

To find the projection of vector BA onto BC, you need to follow these steps:

  1. First, you need to find the unit vector in the direction of BC. This is done by dividing the vector BC by its magnitude. The magnitude of a vector BC = [x, y, z] is calculated as sqrt(x^2 + y^2 + z^2).

  2. Once you have the unit vector of BC, you can find the projection of BA onto BC. This is done by taking the dot product of BA and the unit vector of BC. The dot product of two vectors A = [a1, a2, a3] and B = [b1, b2, b3] is calculated as (a1b1 + a2b2 + a3*b3).

  3. The result of the dot product is a scalar (a single number), and this is the length of the projection of BA onto BC.

  4. If you want the projection as a vector, you multiply the unit vector of BC by the length of the projection. This gives you a vector that has the same direction as BC and the length of the projection of BA onto BC.

Remember that the vectors BA and BC are defined as follows: if A, B and C are points in space with coordinates (xA, yA, zA), (xB, yB, zB) and (xC, yC, zC), then the vectors are BA = [xA - xB, yA - yB, zA - zB] and BC = [xC - xB, yC - yB, zC - zB].

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