Knowee
Questions
Features
Study Tools

The surface shown is a square of side length a. What is the electric flux through the surface? π E a2 E a2 cos(θ) E a2 cos(90° + θ) E a2

Question

The surface shown is a square of side length a. What is the electric flux through the surface? π E a2 E a2 cos(θ) E a2 cos(90° + θ) E a2

🧐 Not the exact question you are looking for?Go ask a question

Solution

The electric flux through a surface is given by the equation Φ = E * A * cos(θ), where E is the electric field, A is the area of the surface, and θ is the angle between the electric field direction and the normal to the surface.

In this case, the surface is a square with side length a, so the area A = a^2.

If the electric field is uniform and perpendicular to the surface, then θ = 0 degrees and cos(θ) = 1. Therefore, the electric flux through the surface is Φ = E * a^2.

If the electric field is at an angle θ to the normal of the surface, then the electric flux is Φ = E * a^2 * cos(θ).

If the electric field is parallel to the surface, then θ = 90 degrees and cos(θ) = 0. Therefore, the electric flux through the surface is Φ = 0.

If the electric field is at an angle of 90° + θ to the normal of the surface, then the electric flux is Φ = E * a^2 * cos(90° + θ).

So, the electric flux through the surface depends on the angle θ

This problem has been solved

Similar Questions

Find the electric flux through the plane surface shown in the figure below if θ = 56°, E = 345 N/C, and d = 4.7 cm. The electric field is uniform over the entire area of the surface and use standard SI units.

A point charge +106.2 𝜇𝐶 is a distance 5 cm directly above the center of a square of side 10 cm,as shown in fig. What is the magnitude of the electric flux through the square? Given∈0 = 8.85 × 10−12𝑁 −1𝐶2𝑚−2

In a region of space, the electric field is given by E⃗ =8iˆ+4jˆ+3kˆ. The electric flux through a surface of area of 100 units in x-y plane is

Find the electric flux through the surface in Figure below*1 point-6 C/εo-3 C/εo+3 C/εo+6 C/εo

An electric field 4.25 N/C produced by a given charged body makes an angle 60° to an area element 20 m^2. What is the electric flux due to the charge?*1 point35.0 Nm^2/C42.5 Nm^2/C43.75 Nm^2/C75.78 Nm^2/C

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.