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A car runs at a constant speed on a circular track of radius 100 m100 m taking 62.8 s62.8 s for every circular lap. The average velocity and average speed for each circular lap respectively, isA0, 00, 0B0, 10 m s−1 0, 10 m s-1 C10 m s−1, 10 m s−110 m s-1, 10 m s-1D10 m s−1, 0

Question

A car runs at a constant speed on a circular track of radius 100 m100 m taking 62.8 s62.8 s for every circular lap. The average velocity and average speed for each circular lap respectively, isA0, 00, 0B0, 10 m s−1 0, 10 m s-1 C10 m s−1, 10 m s−110 m s-1, 10 m s-1D10 m s−1, 0

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Solution

The average velocity of an object moving in a circular path for one complete rotation is always zero because the initial and final positions are the same, so the displacement is zero.

The average speed, on the other hand, is the total distance traveled divided by the total time taken. In this case, the distance traveled is the circumference of the circle, which is 2πr (where r is the radius of the circle).

So, the average speed = total distance / total time = 2π(100 m) / 62.8 s = 10 m/s

Therefore, the average velocity is 0 and the average speed is 10 m/s. So the correct answer is B0, 10 m/s.

This problem has been solved

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