The following scatterplot gives the height and arm span of 15 students.Use the graph and the given trendline, y=1.1007x – 19.049 to predict the arm span of a student who is 181 centimeters tall.(Round your answer to one decimal place, and don't include units (centimeters) in your answer.)
Question
The following scatterplot gives the height and arm span of 15 students.Use the graph and the given trendline, y=1.1007x – 19.049 to predict the arm span of a student who is 181 centimeters tall.(Round your answer to one decimal place, and don't include units (centimeters) in your answer.)
Solution
To predict the arm span of a student who is 181 centimeters tall using the given trendline equation y=1.1007x – 19.049, you need to substitute the height (x) into the equation. Here are the steps:
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Identify the value of x, which is the height of the student. In this case, x = 181 cm.
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Substitute x = 181 into the equation y = 1.1007x – 19.049. This gives y = 1.1007(181) – 19.049.
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Calculate the value of y, which represents the predicted arm span of the student.
Let's do the calculation:
y = 1.1007 * 181 - 19.049 y = 199.1767 - 19.049 y = 180.1277
So, the predicted arm span of a student who is 181 cm tall is approximately 180.1 cm (rounded to one decimal place).
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