Calculate how much storage space is needed to record a 32- bit, 7 khz, stereo music for a duration of 1 hour. (Give in bytes: put the value without symbol)Answer:
Question
Calculate how much storage space is needed to record a 32- bit, 7 khz, stereo music for a duration of 1 hour. (Give in bytes: put the value without symbol)Answer:
Solution
Sure, let's calculate the storage space needed step by step:
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First, we need to know the bit depth, which is 32-bit. This means each sample is stored as a 32-bit number.
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Next, we need to know the sample rate, which is 7 kHz (or 7000 samples per second).
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We also need to know the number of channels, which is 2 (stereo).
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Finally, we need to know the duration of the music, which is 1 hour. We need to convert this to seconds because our sample rate is in samples per second. So, 1 hour = 60 minutes = 3600 seconds.
Now, we can calculate the storage space needed:
Storage space (in bytes) = bit depth (in bits/sample) * sample rate (in samples/second) * number of channels * duration (in seconds)
Substituting the given values:
Storage space (in bytes) = 32 bits/sample * 7000 samples/second * 2 * 3600 seconds
But, we need to convert bits to bytes since 1 byte = 8 bits. So, we divide the total bits by 8 to get bytes:
Storage space (in bytes) = (32/8) bytes/sample * 7000 samples/second * 2 * 3600 seconds
Storage space (in bytes) = 4 bytes/sample * 7000 samples/second * 2 * 3600 seconds
Storage space (in bytes) = 100800000 bytes
So, you would need 100800000 bytes of storage space to record a 32-bit, 7 kHz, stereo music for a duration of 1 hour.
Similar Questions
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