It is believed that 11% of all Americans are left-handed. A college needs to know how many left-handed desks to place in the big lecture halls being constructed on its campus. In a random sample of 370 students from that college, whether or not a student was left-handed was recorded for each student. The college wants to know if the data provide enough evidence to show that students at this college have a different percentage of left-handers than the general American population? State the random variable, population parameter, and hypotheses. State the Type I and Type II errors in the context of this problem.a) The symbol for the random variable involved in this problem is     The wording for the random variable in context is as follows: b) The symbol for the parameter involved in this problem is     The wording for the parameter in context is as follows: c) Fill in the correct null and alternative hypotheses:    𝐻0: 𝐻𝐴: d) A Type I error in the context of this problem would be:    e) A Type II error in the context of this problem would be:

It is believed that 11% of all Americans are left-handed. A college needs to know how many left-handed desks to place in the big lecture halls being constructed on its campus. In a random sample of 240 students of its 24565 students, 31 were left-handed. Does this provide enough evidence to show that students at this college have a higher percentage of left-handers than the general American population? Use a 9% level of significance.P: PARAMETER     What is the correct parameter symbol for this problem?          What is the wording of the parameter in the context of this problem?     H: HYPOTHESES     Fill in the correct null and alternative hypotheses:     𝐻0:      𝐻𝐴: A: ASSUMPTIONS     Since information was collected from each object, what conditions do we need to check?     Check all that apply.     𝑛≥30 or normal population.𝑛𝑝≥10σσ is known.𝑛(1-𝑝̂)≥10𝑁≥20𝑛σσ is unknown.𝑛(1-𝑝)≥10𝑛(𝑝̂)≥10     Check those assumptions:          1. 𝑛𝑝 = which is           2. 𝑛(1-𝑝) = which is           3. 𝑁 = which is               If no N is given in the problem, use 1000000N: NAME THE PROCEDURE     The conditions are met to use a .T: TEST STATISTIC     The symbol and value of the random variable on this problem are as follows:     Leave this answer as a fraction.     =      The formula set up of the test statistic is as follows.:       (Leave any values that were given as fractions as fractions) 𝑧=𝑝̂-𝑝𝑝(1-𝑝)𝑛=( - )/(( ⋅(1- )) / )       Final answer for the test statistic from technology.     Round to 2 decimal places:     z = O: OBTAIN THE P-VALUE     Report to 4 decimal places.     It is possible when rounded that a p-value is 0.0000     P-value = M: MAKE A DECISION     Since the p-value , we .S: STATE A CONCLUSION    There significant evidence to conclude

According to previous studies, 16% of the U.S. population is left-handed. Not knowing this, a high school student claims that the percentage of left-handed people in the U.S. is 15%.The student is going to take a random sample of 2100 people in the U.S. to try to gather evidence to support the claim. Let p be the proportion of left-handed people in the sample.Answer the following. (If necessary, consult a list of formulas.)(a)Find the mean of p.(b)Find the standard deviation of p.(c)Compute an approximation for P≥p0.15, which is the probability that there will be 15% or more left-handed people in the sample. Round your answer to four decimal places.

It is believed that 11% of all Americans are left-handed. In a random sample of 500 students from a particular college with 52407 students, 47 were left-handed. Find a 97% confidence interval for the percentage of all students at this particular college who are left-handed.P: Parameter    What is the correct parameter symbol for this problem?        What is the wording of the parameter in the context of this problem?    A: AssumptionsSince information was collected from each object, what conditions do we need to check?  Check all that apply.   𝑛≥30 or normal population.σσ is known.𝑛(1-𝑝)≥10𝑛(𝑝̂)≥10σσ is unknown.𝑁≥20𝑛𝑛(1-𝑝̂)≥10𝑛𝑝≥10    Check those assumptions:    1. 𝑛𝑝^= which is     2. 𝑛(1-𝑝^)= which is     3. 𝑁= which is          If no N is given in the problem, use 1000000N: Name the procedure     The conditions are met to use a .I: Interval and point estimate    The symbol and value of the point estimate on this problem are as follows:    = Leave answer as a fraction.    The interval estimate for is ( , )    Round endpoints to 3 decimal places.C: Conclusion We are % confident that the is between % and %

Left-handedness occurs in about 12% of all Americans. Males are slightly more likely than females to be left-handed, with 13% of males and 11% of females being left-handed. Suppose a random sample of 80 females and 100 males is chosen.Let X be the number of males (out of the 100) who are left-handed.Let Y be the number of females (out of the 80) who are left-handed.Let Z be the total number of left-handed individuals in the sample (males and females together).Which of the following is true regarding the random variables X and Y? Both X and Y can be well approximated by normal random variables. Only X can be well approximated by a normal random variable. Only Y can be well approximated by a normal random variable. Neither X nor Y can be well approximated by a normal random variable.Question 2Type numbers in the boxes.10 pointsSuppose the time to complete a 200-meter backstroke swim for female competitive swimmers is normally distributed with a mean μ = 141 seconds and a standard deviation σ = 7 seconds. Suppose that to qualify for the Nationals, a woman must complete the 200-meter backstroke in less than 128 seconds. What proportion of competitive female swimmers will qualify for the Nationals? Give your answer to four (4) decimal places.Click here to download the normal table.Question 3Select one answer.10 pointsSuppose the scores on an exam are normally distributed with a mean μ = 75 points and standard deviation σ = 8 points.What is the exam score for an exam whose z-score is 1.25? 65 75 85 0.8944 0.1056

A statistics student has heard that about 19% of the students on his campus attend sporting eventsweekly. He wants to know if statistics students attend events in the same proportions as the generalstudent body. Explain what type II error would be in this caseA) Type II error would be saying that there is no difference in the attendance of statistics students andthe student body as a whole at sporting events, even though statistics students actually go much lessoften.B) Type II error would be saying that statistics students attend sporting events in different proportionsthan the student body as a whole, even though they actually have the same attendance proportion.C) Type II error would be saying that there is no difference in the attendance of statistics students andthe student body as a whole at sporting events, even though there really is.D) Type II error would be saying that statistics students attend sporting events in much higherproportions than the student body as a whole, even though they actually have the same attendanceproportion