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At a dog show, a Maltese, a Dachshund, a Golden Retriever, a Greyhound, a Weimaraner, a Husky, a Great Dane, and a Cocker Spaniel won first place in their divisions. In how many different orders could these winners be announced?

Question

At a dog show, a Maltese, a Dachshund, a Golden Retriever, a Greyhound, a Weimaraner, a Husky, a Great Dane, and a Cocker Spaniel won first place in their divisions. In how many different orders could these winners be announced?

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Solution

The problem is asking for the number of ways to arrange 8 different items, which is a permutation problem.

The formula for permutations is n!, where n is the number of items to arrange and "!" denotes factorial, which means multiplying all positive integers from 1 to n.

In this case, there are 8 dogs, so n = 8.

So, the number of different orders the winners could be announced is 8! = 8765432*1 = 40,320.

This problem has been solved

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