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The value of a diamond varies directly with the square of its weight. A diamond is cut into three pieces whose weights are in the ratio 3 : 4 : 5. Consequently, by what percentage does the value of the diamond diminish?

Question

The value of a diamond varies directly with the square of its weight. A diamond is cut into three pieces whose weights are in the ratio 3 : 4 : 5. Consequently, by what percentage does the value of the diamond diminish?

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Solution

To solve this problem, we need to understand the relationship between the value of a diamond and its weight. The problem states that the value of a diamond varies directly with the square of its weight. This means that if we double the weight of the diamond, its value will increase by a factor of four (since 2^2 = 4).

The problem also states that a diamond is cut into three pieces whose weights are in the ratio 3 : 4 : 5. This means that the total weight of the diamond is divided into 12 parts (since 3 + 4 + 5 = 12).

Let's assume that the original weight of the diamond is W. Then, the weights of the three pieces are 3W/12, 4W/12, and 5W/12 respectively.

The value of the diamond before it was cut is proportional to the square of its weight, or (W^2).

After the diamond is cut, the total value of the three pieces is proportional to the sum of the squares of their weights, or (3W/12)^2 + (4W/12)^2 + (5W/12)^2.

Simplify this to get 9W^2/144 + 16W^2/144 + 25W^2/144 = 50W^2/144.

The percentage by which the value of the diamond diminishes is given by the difference between the original value and the new value, divided by the original value, times 100%.

So, the percentage diminution in value is ((W^2 - 50W^2/144) / W^2) * 100% = (94/144)*100% = 65.28%.

Therefore, the value of the diamond diminishes by approximately 65.28% when it is cut into three pieces whose weights are in the ratio 3 : 4 : 5.

This problem has been solved

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