Describe the shape and polarity of the molecule, OCSe.Group of answer choicesIt is linear and polar with the O end more positive than the Se end.It is linear and polar with the Se end more positive than the O end.It is angular with the C end more positive.It is linear and non-polar.It is angular and non-polar.
Question
Describe the shape and polarity of the molecule, OCSe.Group of answer choicesIt is linear and polar with the O end more positive than the Se end.It is linear and polar with the Se end more positive than the O end.It is angular with the C end more positive.It is linear and non-polar.It is angular and non-polar.
Solution
The molecule OCSe is linear and polar with the O end more positive than the Se end.
Here's why:
-
Shape: The central atom in this molecule is Carbon (C), which is bonded to Oxygen (O) and Selenium (Se). Both Oxygen and Selenium are group 16 elements, so they form two pairs of electrons with Carbon. This results in a linear shape for the molecule.
-
Polarity: Oxygen is more electronegative than Selenium, meaning it has a greater ability to attract electrons. Therefore, the electrons in the C-O bond are more likely to be found near the Oxygen atom, making the O end of the molecule more negative. Conversely, the Se end of the molecule is more positive.
So, the correct answer is: It is linear and polar with the O end more positive than the Se end.
Similar Questions
Predict the geometry and polarity of the CS2 molecule.linear, polarlinear, nonpolartetrahedral, nonpolarbent, nonpolarbent, polar
3. Which of the following bonds would be the least polar yet still be considered polar covalent? 1 pointMg-OC-OO-OSi-ON-O
Which of the following bonds would be the most polar without being considered ionic?A) Mg-OB) C-OC) O-OD) Si-OE) N-O
Which of the following structures is / are polar?Data:
Which of the following molecules is the most polar?
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.