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Select the correct answerFor the program given below, what will be the output after its execution?public class Nptel extends Thread { public static void main(String[] args) { Thread thread = Thread.currentThread(); System.out.println(thread.activeCount()); }}Optionstrue01false

Question

Select the correct answerFor the program given below, what will be the output after its execution?public class Nptel extends Thread { public static void main(String[] args) { Thread thread = Thread.currentThread(); System.out.println(thread.activeCount()); }}Optionstrue01false

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Solution

The correct answer is 1.

Here's the step by step explanation:

  1. The main method is a static method and it is part of the Nptel class. When the Java Virtual Machine (JVM) calls the main method, it creates a new thread of execution. This thread is often referred to as the "main" thread, because it is the one that is executed when your program starts.

  2. The line Thread thread = Thread.currentThread(); gets a reference to the currently executing thread, which is the "main" thread.

  3. The activeCount() method returns the number of active threads in the current thread's thread group. Since there is only one thread (the "main" thread) at this point, the output of System.out.println(thread.activeCount()); will be 1.

So, the output of the program will be 1.

This problem has been solved

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