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Which of the following is the correct output for the following JavaScript code:var x=3;  var y=2;  var z=0;  If(x==y)  document.write(x);  elseif(x==y)  document.write(x);  else  document.write(z);  Question 3Select one:a.3b.0c.2d.Error

Question

Which of the following is the correct output for the following JavaScript code:var x=3;  var y=2;  var z=0;  If(x==y)  document.write(x);  elseif(x==y)  document.write(x);  else  document.write(z);  Question 3Select one:a.3b.0c.2d.Error

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Solution

The correct answer is b.0.

Here's the step-by-step explanation:

  1. The code first declares three variables: x, y, and z, with values 3, 2, and 0 respectively.
  2. Then it checks if x is equal to y (if x==y). In this case, x is 3 and y is 2, so they are not equal. Therefore, the code inside this if statement (document.write(x);) is not executed.
  3. Then it checks the next condition (elseif(x==y)). This is the same condition as before, and it's still false, so the code inside this elseif statement (document.write(x);) is also not executed.
  4. Since none of the previous conditions were met, the code inside the else statement (document.write(z);) is executed. This writes the value of z, which is 0, to the document.
  5. Therefore, the output of this code is 0.

This problem has been solved

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