Which of the following is the correct output for the following JavaScript code:var x=3; var y=2; var z=0; If(x==y) document.write(x); elseif(x==y) document.write(x); else document.write(z); Question 3Select one:a.3b.0c.2d.Error
Question
Which of the following is the correct output for the following JavaScript code:var x=3; var y=2; var z=0; If(x==y) document.write(x); elseif(x==y) document.write(x); else document.write(z); Question 3Select one:a.3b.0c.2d.Error
Solution
The correct answer is b.0.
Here's the step-by-step explanation:
- The code first declares three variables: x, y, and z, with values 3, 2, and 0 respectively.
- Then it checks if x is equal to y (if x==y). In this case, x is 3 and y is 2, so they are not equal. Therefore, the code inside this if statement (document.write(x);) is not executed.
- Then it checks the next condition (elseif(x==y)). This is the same condition as before, and it's still false, so the code inside this elseif statement (document.write(x);) is also not executed.
- Since none of the previous conditions were met, the code inside the else statement (document.write(z);) is executed. This writes the value of z, which is 0, to the document.
- Therefore, the output of this code is 0.
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