In rabbits, there is a gene that controls ear length, with a dominant allele "T" for long ears and a recessive allele "t" for short ears. At another gene locus, there are alleles “B” for black coat and “W” for white coat. Neither the B or W allele is dominant, and BW produces a gray coat. These two allele pairs assort independently. If a gray rabbit that is heterozygous at the gene locus controlling ear length is mated with a white rabbit that is also heterozygous at the gene locus controlling ear length, what is the probability that their first offspring will be gray with long ears?Multiple Choice1/83/83/161/161/2
Question
In rabbits, there is a gene that controls ear length, with a dominant allele "T" for long ears and a recessive allele "t" for short ears. At another gene locus, there are alleles “B” for black coat and “W” for white coat. Neither the B or W allele is dominant, and BW produces a gray coat. These two allele pairs assort independently. If a gray rabbit that is heterozygous at the gene locus controlling ear length is mated with a white rabbit that is also heterozygous at the gene locus controlling ear length, what is the probability that their first offspring will be gray with long ears?Multiple Choice1/83/83/161/161/2
Solution
The first step is to determine the genotypes of the parent rabbits. The gray rabbit is BW for coat color and Tt for ear length (since it's heterozygous). The white rabbit is WW for coat color and Tt for ear length (since it's also heterozygous).
Next, we need to determine the possible genotypes of the offspring. We can do this by creating a Punnett square for each gene locus.
For the coat color, the possible genotypes are:
- BW (from the gray rabbit) x WW (from the white rabbit) = BW, BW, WW, WW. So, the probability of an offspring being gray (BW) is 1/2.
For the ear length, the possible genotypes are:
- Tt (from the gray rabbit) x Tt (from the white rabbit) = TT, Tt, Tt, tt. So, the probability of an offspring having long ears (either TT or Tt) is 3/4.
Finally, to find the probability of an offspring being gray with long ears, we multiply the probabilities of the two independent events. So, the probability is 1/2 (for gray coat) x 3/4 (for long ears) = 3/8.
So, the correct answer is 3/8.
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