You have an input volume that is 15*15*8. You convolve it with 10 filters of size 3*3 using stride=2 and pad=2. What is the dimension of the resulting volume?a.9*9*10b.9*9*12c.9*9*8d.9*9*3
Question
You have an input volume that is 15158. You convolve it with 10 filters of size 33 using stride=2 and pad=2. What is the dimension of the resulting volume?a.9910b.9912c.998d.99*3
Solution
The dimension of the resulting volume can be calculated using the formula for the spatial dimensions of the output volume (height and width) after convolution:
output_dim = 1 + (input_dim - filter_dim + 2*pad) / stride
Here, the input_dim is 15 (since the input is 15x15), the filter_dim is 3 (since the filter is 3x3), the pad is 2, and the stride is 2.
So, the output_dim would be:
output_dim = 1 + (15 - 3 + 2*2) / 2 = 9
The depth of the output volume is equal to the number of filters, which is 10 in this case.
So, the dimension of the resulting volume is 9x9x10. Therefore, the correct answer is a. 9910.
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