How many moles of carbon tetrachloride are present in 18.0g of CCl4?
Question
How many moles of carbon tetrachloride are present in 18.0g of CCl4?
Solution
To find the number of moles in 18.0g of Carbon Tetrachloride (CCl4), you need to know the molar mass of CCl4.
Step 1: Calculate the molar mass of CCl4. The molar mass of carbon (C) is approximately 12.01 g/mol, and the molar mass of chlorine (Cl) is approximately 35.45 g/mol. Since there are 4 chlorine atoms in CCl4, you multiply the molar mass of chlorine by 4.
Molar mass of CCl4 = (12.01 g/mol) + 4*(35.45 g/mol) = 153.81 g/mol
Step 2: Use the formula for moles which is mass (g) divided by molar mass (g/mol).
Number of moles = mass ÷ molar mass = 18.0g ÷ 153.81 g/mol = 0.117 moles
So, there are approximately 0.117 moles of Carbon Tetrachloride in 18.0g.
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