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A triangle ABC is inscribed in a circle, and the bisectors of the angle ∠A, ∠B and ∠C meet the circumference at X, Y, Z respectively. The angles of the triangle X, Y, Z are respectively

Question

A triangle ABC is inscribed in a circle, and the bisectors of the angle ∠A, ∠B and ∠C meet the circumference at X, Y, Z respectively. The angles of the triangle X, Y, Z are respectively

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Solution

The angles of the triangle XYZ are 90° - A/2, 90° - B/2, and 90° - C/2 respectively.

Here's the step-by-step explanation:

  1. The angle bisectors of a triangle intersect the circumcircle at points that form another triangle, in this case XYZ.

  2. The angles of triangle XYZ are related to the angles of the original triangle ABC. Specifically, each angle of triangle XYZ is equal to 90° minus half the corresponding angle of triangle ABC.

  3. Therefore, the angles of triangle XYZ are 90° - A/2, 90° - B/2, and 90° - C/2 respectively.

This problem has been solved

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