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For the following excerpt of WRAMP assembly code, what are the final values stored in $2and $3?(2 marks)addi $2, $0, 0x42addi $3, $0, 0x42andi $2, $2, 0xF0andi $2, $2, 0xF0xori $3, $3, 0xF0xori $3, $3, 0xF0

Question

For the following excerpt of WRAMP assembly code, what are the final values stored in 2and2and 3?(2 marks)addi 2,2, 0, 0x42addi 3,3, 0, 0x42andi 2,2, 2, 0xF0andi 2,2, 2, 0xF0xori 3,3, 3, 0xF0xori 3,3, 3, 0xF0

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Solution

The WRAMP assembly code provided performs a series of operations on registers 2and2 and 3. Here's a step-by-step breakdown of the operations and the resulting values:

  1. addi $2, $0, 0x42: This instruction adds the immediate value 0x42 to the value in register 0(whichisalways0),andstorestheresultinregister0 (which is always 0), and stores the result in register 2. So, $2 = 0x42.

  2. addi $3, $0, 0x42: This instruction does the same as the previous one, but stores the result in register 3.So,3. So, 3 = 0x42.

  3. andi $2, $2, 0xF0: This instruction performs a bitwise AND operation between the value in register 2(0x42)andtheimmediatevalue0xF0.Theresultis0x40,whichisstoredbackin2 (0x42) and the immediate value 0xF0. The result is 0x40, which is stored back in 2. So, $2 = 0x40.

  4. andi $2, $2, 0xF0: This instruction is repeated, but since the value in 2isalready0x40,theresultremainsthesame.So,2 is already 0x40, the result remains the same. So, 2 = 0x40.

  5. xori $3, $3, 0xF0: This instruction performs a bitwise XOR operation between the value in register 3(0x42)andtheimmediatevalue0xF0.Theresultis0xB2,whichisstoredbackin3 (0x42) and the immediate value 0xF0. The result is 0xB2, which is stored back in 3. So, $3 = 0xB2.

  6. xori $3, $3, 0xF0: This instruction is repeated. The XOR operation between 0xB2 and 0xF0 results in 0x42. So, $3 = 0x42.

So, the final values stored in the registers are 2=0x40and2 = 0x40 and 3 = 0x42.

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