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A farmer owns a total of 32 chickens and sheeps.The chickens and sheeps have 116 legs altogether.How many sheeps are there?

Question

A farmer owns a total of 32 chickens and sheeps.The chickens and sheeps have 116 legs altogether.How many sheeps are there?

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Solution

To solve this problem, we can use a system of linear equations.

Let's denote: C - the number of chickens S - the number of sheep

From the problem, we know two things:

  1. The farmer owns a total of 32 chickens and sheep. This can be written as: C + S = 32
  2. The chickens and sheep have 116 legs altogether. Chickens have 2 legs and sheep have 4 legs. This can be written as: 2C + 4S = 116

We can simplify the second equation by dividing the entire equation by 2, which gives us: C + 2S = 58

Now we have a system of two equations:

C + S = 32 C + 2S = 58

By subtracting the first equation from the second, we get: S = 58 - 32 = 26

So, the farmer has 26 sheep.

This problem has been solved

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