A photograph of a bacteria enlarged 50,000 times attains a length of 5 cm. What is the actuallength of the bacteria? If the photograph is enlarged 20,000 times only, what would be its enlargedlength?
Question
A photograph of a bacteria enlarged 50,000 times attains a length of 5 cm. What is the actuallength of the bacteria? If the photograph is enlarged 20,000 times only, what would be its enlargedlength?
Solution
To solve this problem, we need to follow these steps:
Step 1: Find the actual length of the bacteria The photograph of the bacteria is enlarged 50,000 times to attain a length of 5 cm. Therefore, the actual length of the bacteria is 5 cm divided by 50,000.
Step 2: Find the enlarged length of the bacteria if the photograph is enlarged 20,000 times only The actual length of the bacteria (found in step 1) multiplied by 20,000 will give us the enlarged length of the bacteria if the photograph is enlarged 20,000 times only.
Let's calculate:
Step 1: Actual length of bacteria = 5 cm / 50,000 = 0.0001 cm
Step 2: Enlarged length if the photograph is enlarged 20,000 times = 0.0001 cm * 20,000 = 2 cm
So, the actual length of the bacteria is 0.0001 cm and if the photograph is enlarged 20,000 times, the length of the bacteria would be 2 cm.
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