From a 2.507 g sample containing only iron, sand, and salt, 0.909 g of iron and 1.114 g of sand were separated and recovered.What was the percent of salt in the original sample?Type answer:
Question
From a 2.507 g sample containing only iron, sand, and salt, 0.909 g of iron and 1.114 g of sand were separated and recovered.What was the percent of salt in the original sample?Type answer:
Solution
To find the percent of salt in the original sample, we first need to determine the mass of the salt. We can do this by subtracting the mass of the iron and the sand from the total mass of the sample.
The total mass of the sample is 2.507 g. The mass of the iron is 0.909 g and the mass of the sand is 1.114 g.
So, the mass of the salt is 2.507 g - 0.909 g - 1.114 g = 0.484 g.
To find the percent of salt, we divide the mass of the salt by the total mass of the sample and then multiply by 100.
So, the percent of salt is (0.484 g / 2.507 g) * 100 = 19.31%.
Therefore, the percent of salt in the original sample is 19.31%.
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