When treated with excess LiAlH4, acid chlorides are reduced to give which of the following?Select answer from the options belowSecondary alcoholsPrimary alcoholsEstersAldehydes
Question
When treated with excess LiAlH4, acid chlorides are reduced to give which of the following?Select answer from the options belowSecondary alcoholsPrimary alcoholsEstersAldehydes
Solution
When treated with excess LiAlH4, acid chlorides are reduced to give primary alcohols.
Here's a step-by-step explanation:
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Lithium aluminium hydride (LiAlH4) is a strong reducing agent.
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When an acid chloride is treated with LiAlH4, the LiAlH4 reduces the acid chloride by donating hydride (H-) ions.
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The carbonyl carbon of the acid chloride (C=O) is electron deficient and hence, it accepts the hydride ions from LiAlH4.
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This results in the reduction of the acid chloride to an alcohol.
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Since the acid chloride only has one carbonyl group that can be reduced, the product of this reaction is a primary alcohol.
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