What will be the output of the following code?#include <stdio.h>int main() {    int arr[4] = {0, 1, 2, 3};    printf("%d\n", arr[-1]);    return 0;}

The code will result in undefined behavior. In C, array indexing is based on offset from the base address. So, arr[-1] is trying to access the memory location before the start of the array, which is not defined. It might crash or it might print some garbage value, depending on the system and compiler.