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In the last few minutes of a diving team practice, there is time for 2 of the 6 divers to line up and do a particular dive. How many sequences of 2 divers are possible?

Question

In the last few minutes of a diving team practice, there is time for 2 of the 6 divers to line up and do a particular dive. How many sequences of 2 divers are possible?

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Solution

The problem can be solved using the concept of permutations in combinatorics.

A permutation is an arrangement of objects in a specific order. The number of permutations of n objects taken r at a time is given by the formula:

P(n, r) = n! / (n-r)!

where "!" denotes factorial, which is the product of all positive integers up to that number.

In this case, we have 6 divers (n=6) and we want to know how many sequences are possible for 2 divers (r=2).

So, we plug these values into the formula:

P(6, 2) = 6! / (6-2)!

= 720 / 24

= 30

So, there are 30 different sequences of 2 divers possible.

This problem has been solved

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