The function ff is defined by f, of, x, equals, 2, x, cubed, plus, 2, x, minus, 4f(x)=2x 3 +2x−4 and the point left bracket, 0, comma, minus, 4, right bracket(0,−4) is on the graph of f, .f. If g, of, x, equals, f, to the power minus 1 , left bracket, x, right bracketg(x)=f −1 (x), what is the value of g, prime, of, minus, 4, question markg ′ (−4)?
Question
The function ff is defined by f, of, x, equals, 2, x, cubed, plus, 2, x, minus, 4f(x)=2x 3 +2x−4 and the point left bracket, 0, comma, minus, 4, right bracket(0,−4) is on the graph of f, .f. If g, of, x, equals, f, to the power minus 1 , left bracket, x, right bracketg(x)=f −1 (x), what is the value of g, prime, of, minus, 4, question markg ′ (−4)?
Solution
To find the value of g′(−4), we first need to find the derivative of the inverse function f(x).
Step 1: Find the derivative of f(x) f'(x) = 6x^2 + 2
Step 2: Evaluate f'(x) at x = 0 (since the point (0, -4) is on the graph of f(x), the point (-4, 0) is on the graph of f^(-1)(x)) f'(0) = 6*0^2 + 2 = 2
Step 3: Use the formula for the derivative of an inverse function g′(x) = 1 / f'(f^(-1)(x))
Step 4: Substitute x = -4 into the formula g′(-4) = 1 / f'(f^(-1)(-4))
Step 5: Since f^(-1)(-4) = 0 (from the point (-4, 0) on the graph of f^(-1)(x)), we can substitute 0 into the formula g′(-4) = 1 / f'(0) = 1 / 2 = 0.5
So, the value of g′(−4) is 0.5.
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