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Which of the following algorithm is the optimal way to find the middle element of the linked list?radio_button_uncheckedFind the length of the Linked List and then traverse again to the n/2th Noderadio_button_unchecked Fast and slow pointer methodradio_button_uncheckedFind the distance of all nodes and print the middle nodesradio_button_uncheckedNone of these

Question

Which of the following algorithm is the optimal way to find the middle element of the linked list?radio_button_uncheckedFind the length of the Linked List and then traverse again to the n/2th Noderadio_button_unchecked Fast and slow pointer methodradio_button_uncheckedFind the distance of all nodes and print the middle nodesradio_button_uncheckedNone of these

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Solution

The optimal way to find the middle element of the linked list is the "Fast and slow pointer method".

Here's why:

  1. Initialize two pointers, slow and fast, at the head of the linked list.
  2. Move the slow pointer by one node at a time, and the fast pointer by two nodes at a time.
  3. When the fast pointer reaches the end of the list, the slow pointer will be at the middle of the list.

This method only requires a single traversal of the list, making it more efficient than the other options.

This problem has been solved

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The optimal Time complexity to reverse a Linked List (Singly LL) is ______.radio_button_uncheckedO(n)radio_button_uncheckedO(1)     radio_button_uncheckedO(logn)            radio_button_uncheckedNone of these

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