The equation of a circle in the coordinate plane with center (h, k) and radius r is given by the formula:

(x - h)² + (y - k)² = r²

Given that the center of the circle is (1, -4) and the radius is 2, we can substitute these values into the formula to get the equation of the circle:

(x - 1)² + (y - (-4))² = 2²

Simplifying this gives:

(x - 1)² + (y + 4)² = 4

So, the equation of the circle with center (1, -4) and radius 2 is (x - 1)² + (y + 4)² = 4.

Question

The equation of a circle in the coordinate plane with center (h, k) and radius r is given by the formula:

(x - h)² + (y - k)² = r²

Given that the center of the circle is (1, -4) and the radius is 2, we can substitute these values into the formula to get the equation of the circle:

(x - 1)² + (y - (-4))² = 2²

Simplifying this gives:

(x - 1)² + (y + 4)² = 4

So, the equation of the circle with center (1, -4) and radius 2 is (x - 1)² + (y + 4)² = 4.

Knowee AI · Accepted Answer

The equation of a circle in the coordinate plane with center (h, k) and radius r is given by the formula:

(x - h)² + (y - k)² = r²

Given that the center of the circle is (1, -4) and the radius is 2, we can substitute these values into the formula to get the equation of the circle:

(x - 1)² + (y - (-4))² = 2²

Simplifying this gives:

(x - 1)² + (y + 4)² = 4

So, the equation of the circle with center (1, -4) and radius 2 is (x - 1)² + (y + 4)² = 4.

What is the equation of a circle with center (1, -4) and radius 2?A.B.C.D.

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