Forty-eight participants are divided into two different-sized groups and asked to play a game while very, very hungry. Given that their pooled variance estimate is 7.19, when conducting a t-test to compare the two groups scores, approximately what would the standard error of the distribution of sample mean differences be? cannot say based on the information given 0.15 0.77 0.39
Question
Forty-eight participants are divided into two different-sized groups and asked to play a game while very, very hungry. Given that their pooled variance estimate is 7.19, when conducting a t-test to compare the two groups scores, approximately what would the standard error of the distribution of sample mean differences be? cannot say based on the information given 0.15 0.77 0.39
Solution
Based on the information given, it is not possible to determine the standard error of the distribution of sample mean differences. This is because we do not have information about the sample sizes of the two groups. The standard error of the distribution of sample mean differences is calculated by taking the square root of the sum of the variances divided by their respective sample sizes. Without this information, we cannot perform the calculation. Therefore, the answer is "cannot say based on the information given".
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