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The standing wave in this spring has a frequency of 0.954 Hz. If the spring is stretched to a length of 4.50 m,the speed of the wave in the spring isa. 2.15 m/s c. 4.72 m/sb. 2.36 m/s d. 4.29 mls

Question

The standing wave in this spring has a frequency of 0.954 Hz. If the spring is stretched to a length of 4.50 m,the speed of the wave in the spring isa. 2.15 m/s c. 4.72 m/sb. 2.36 m/s d. 4.29 mls

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Solution

The speed of a wave can be calculated using the formula:

v = f * λ

where: v is the speed of the wave, f is the frequency of the wave, and λ is the wavelength of the wave.

In a standing wave on a stretched spring, the length of the spring is equal to half the wavelength (since there are two nodes, one at each end of the spring). Therefore, we can say that:

λ = 2 * length of the spring

Substituting the given values into the equations:

f = 0.954 Hz length of the spring = 4.50 m

we find:

λ = 2 * 4.50 m = 9.00 m

Then we substitute f and λ into the speed equation:

v = 0.954 Hz * 9.00 m = 8.586 m/s

However, this value does not match any of the provided options. Please check the problem statement and the provided options again.

This problem has been solved

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