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If a bee flies from a petunia to a marigold, and then returns to the petunia,Group of answer choiceshis average speed was greater than his average velocity.his average velocity was greater than his average speed.his average speed was equal to his average velocity.

Question

If a bee flies from a petunia to a marigold, and then returns to the petunia,Group of answer choiceshis average speed was greater than his average velocity.his average velocity was greater than his average speed.his average speed was equal to his average velocity.

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Solution

His average speed was equal to his average velocity.

Here's why:

Speed is a scalar quantity that refers to "how fast an object is moving." On the other hand, velocity is a vector quantity that refers to "the speed in a specific direction."

In this case, the bee is returning to its original position (the petunia). This means the total displacement (change in position) is zero.

Average velocity is calculated as total displacement divided by total time. Since the displacement is zero, the average velocity is also zero.

Average speed is calculated as total distance traveled divided by total time. The bee traveled a certain distance to the marigold and the same distance back to the petunia. This distance is greater than zero.

However, in this context, when we say "average speed," we're referring to the magnitude (or absolute value) of the average velocity. Since the bee ends up back at its starting point, the magnitude of its average velocity is the same as its average speed.

So, his average speed was equal to his average velocity.

This problem has been solved

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