Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target.You may assume that each input would have exactly one solution, and you may not use the same element twice.
Question
Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target.You may assume that each input would have exactly one solution, and you may not use the same element twice.
Solution 1
Sure, here is a Python solution for the problem using a dictionary to store the numbers and their indices.
def twoSum(nums, target):
if len(nums) <= 1:
return False
buff_dict = {}
for i in range(len(nums)):
if nums[i] in buff_dict:
return [buff_dict[nums[i]], i]
else:
buff_dict[target - nums[i]] = i
Here is a step by step explanation of the code:
-
Check if the length of the list is less than or equal to 1. If it is, return False because there are not enough numbers to add up to the target.
-
Create an empty dictionary called
buff_dict. -
Loop through the list of numbers. For each number:
-
Check if the number is in
buff_dict. If it is, that means we have found two numbers that add up to the target. Return a list containing the index of the number inbuff_dictand the current index. -
If the number is not in `buff
-
Solution 2
No answer
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