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Suppose we want to choose 2 objects, without replacement, from the 5 objects pencil, eraser, desk, chair, and lamp.(If necessary, consult a list of formulas.)(a) How many ways can this be done, if the order of the choices is relevant?(b) How many ways can this be done, if the order of the choices is not relevant?

Question

Suppose we want to choose 2 objects, without replacement, from the 5 objects pencil, eraser, desk, chair, and lamp.(If necessary, consult a list of formulas.)(a) How many ways can this be done, if the order of the choices is relevant?(b) How many ways can this be done, if the order of the choices is not relevant?

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Solution

(a) If the order of the choices is relevant, we use the permutation formula. The number of ways to choose 2 objects from 5 is given by P(5,2) = 5! / (5-2)! = 20 ways.

(b) If the order of the choices is not relevant, we use the combination formula. The number of ways to choose 2 objects from 5 is given by C(5,2) = 5! / [2!(5-2)!] = 10 ways.

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