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A container has 20 liters of a solution containing alcohol and water in the ratio of 3:2. How many liters of water should be added to make the ratio 3:4? Options 4 8 6 10

Question

A container has 20 liters of a solution containing alcohol and water in the ratio of 3:2. How many liters of water should be added to make the ratio 3:4?

Options 4

8

6

10

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Solution

Let's solve this step by step:

  1. The initial volume of the solution is 20 liters, and the ratio of alcohol to water is 3:2. This means that the solution contains 12 liters of alcohol and 8 liters of water (because 20 liters * 3/5 = 12 liters of alcohol and 20 liters * 2/5 = 8 liters of water).

  2. We want to add water to change the ratio to 3:4. This means that for every 3 parts of alcohol, we need 4 parts of water. Since the amount of alcohol remains constant at 12 liters, we can set up the following equation to find the new amount of water needed:

    12 liters (alcohol) / 3 = x liters (water) / 4

  3. Solving for x gives us x = 16 liters. This is the total amount of water we need in the new solution.

  4. Since we already have 8 liters of water in the solution, we need to add 16 liters - 8 liters = 8 liters of water.

So, the correct answer is 8 liters.

This problem has been solved

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