From the top of a tower, a stone is thrown up. It reaches the ground in time t1. A secondstone thrown down with the same speed reaches the ground in time t2. A third stonereleased from rest reaches the ground in time t3. Then :(1) t3=2tt21(2) t3=21tt(3)213t1t1t

A girl dropped a stone from the top of a tower 45m tall and a boy projected another stone vertically upwards at 25m/s at the same time. Determine the time taken for the two stones to meet.

A stone is dropped from the top of a tower travels 25m in the last second of itsmotion. If 210 /g m s height of the tower isA) 54m B) 45m C) 25m D) 64m

A stone is allowed to fall from the top of a tower 100 m high and at the same time another stone is projected vertically upwards from the ground with a velocity of 25 m/s. Calculate when and where the two stones will meet.

We know that the stone's velocity was −152 ft/s when it hit the ground. Therefore, since v(t) = −32t, the time when the stone hit the ground wast = s.

A stone is released from the top of a tower of height 980 m. Calculate its velocity after 3 seconds. (Take g = 9.8 m/s2)