Find the least possible 4 digit number, which when divided by 10, 12, 16 and 20 leaves the remainder 27.1 point1247123013001227

The least possible 4 digit number that leaves a remainder of 27 when divided by 10, 12, 16, and 20 is 1027.

Here's how you can find it:

Step 1: Find the least common multiple (LCM) of the divisors. The LCM of 10, 12, 16, and 20 is 240.

Step 2: The least 4 digit number divisible by 240 is 960.

Step 3: Add the remainder to this number. So, 960 + 27 = 987. But this is not a 4 digit number.

Step 4: The next number divisible by 240 is 960 + 240 = 1200.

Step 5: Add the remainder to this number. So, 1200 + 27 = 1227. But this number does not leave a remainder of 27 when divided by 16.

Step 6: The next number divisible by 240 is 1200 + 240 = 1440.

Step 7: Add the remainder to this number. So, 1440 + 27 = 1467. But this number does not leave a remainder of 27 when divided by 16.

Step 8: Continue this process until you find a 4 digit number that leaves a remainder of 27 when divided by all the divisors. The number is 1027.