ose we are given the following.Line 1 passes through , −47 and , −22.

To find the equation of the line passing through the points (-4, 7) and (-2, 2), we can use the slope-intercept form of a linear equation, which is y = mx + b, where m is the slope and b is the y-intercept.

Step 1: Find the slope (m) using the formula: m = (y2 - y1) / (x2 - x1)

Given the points (-4, 7) and (-2, 2), we can substitute the values into the formula: m = (2 - 7) / (-2 - (-4)) m = -5 / 2

Step 2: Substitute the slope (m) and one of the points (x1, y1) into the slope-intercept form equation: y = mx + b Using the point (-4, 7): 7 = (-5/2)(-4) + b

Step 3: Solve for b: 7 = 10 + b b = 7 - 10 b = -3

Step 4: Write the equation of the line using the slope (m) and y-intercept (b): y = (-5/2)x - 3

Therefore, the equation of the line passing through the points (-4, 7) and (-2, 2) is y = (-5/2)x - 3.