Find the n-factor the half equation for the oxidation of sulphite ion :SO2−3(aq)+H2O→SO2−4(aq)+2H+(aq)+2e−
Question
Find the n-factor the half equation for the oxidation of sulphite ion :SO2−3(aq)+H2O→SO2−4(aq)+2H+(aq)+2e−
Solution
The n-factor in a redox reaction is the total change in the oxidation number per molecule. In the given half equation for the oxidation of sulphite ion:
SO2−3(aq) + H2O → SO2−4(aq) + 2H+(aq) + 2e−
The oxidation state of sulfur changes from +4 in SO2−3 to +6 in SO2−4. Therefore, the change in oxidation state is +6 - (+4) = +2.
So, the n-factor for this half equation is 2.
Similar Questions
Write the equilibrium constant expression for this reaction:2H+(aq)+SO2−4(aq) → H2SO4(aq)
Calculate the n-factor of S2O3 for the following change.2S2O2−3→S4O2−6+2e−
Determine the oxidation number of Sulfur atom in Ca(HSO4)2
Write the ionic equation for the reaction between lead(II) nitrate(aq) + magnesium sulfate(aq) magnesium nitrate(aq) + lead(II) sulfate(s)
Write the oxidation and reduction half-reactions (without states of matter) for the following reaction:→+Cas 2Ag+aq + Ca2+aq 2Ags
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.