What is the oxidation number of nitrogen in Fe(NO2)3? (A) +5 (B) +4 (C) +3 (D) –3 explain the answer when you get it and explain how to find the oxidation states for other elements.

The oxidation number of nitrogen in Fe(NO2)3 can be found by understanding the rules of oxidation numbers and applying them to this compound.

1. The oxidation number of an atom in its elemental form is always 0.

2. The oxidation number of a monatomic ion is equal to its charge.

3. Oxygen usually has an oxidation number of -2 in its compounds (except in peroxides where it's -1, and in compounds with fluorine where it's positive).

4. The sum of the oxidation numbers in a neutral compound is 0, while in an ion it's equal to the ion's charge.

Now, let's apply these rules to Fe(NO2)3.

In NO2, oxygen has an oxidation number of -2 (rule 3). Since there are two oxygen atoms, the total oxidation number for oxygen is -4.

The compound NO2 must have a total oxidation number of 0 (rule 4), so the oxidation number of nitrogen (N) must be +4 to balance out the -4 from the oxygen.

Therefore, the oxidation number of nitrogen in Fe(NO2)3 is +4, so the correct answer is (B) +4.

To find the oxidation states for other elements, you would follow the same rules. Start with the known oxidation states (like oxygen and hydrogen), and then use the fact that the total oxidation number must be 0 (for neutral compounds) or equal to the charge (for ions) to find the unknown oxidation states.