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11.If the index of refraction for water 1.33 and the speed of light in vacuum is 3 × 108 m/s.ABCD

Question

11.If the index of refraction for water 1.33 and the speed of light in vacuum is 3 × 108 m/s.ABCD

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Solution

Para resolver esta pregunta, necesitamos usar la fórmula que relaciona el índice de refracción con la velocidad de la luz en el vacío y la velocidad de la luz en el medio:

n=cv n = \frac{c}{v}

donde:

  • n n es el índice de refracción del medio (en este caso, agua).
  • c c es la velocidad de la luz en el vacío (3 × 10^8 m/s).
  • v v es la velocidad de la luz en el medio (agua).

Dado que el índice de refracción del agua es 1.33, podemos reorganizar la fórmula para encontrar v v :

v=cn v = \frac{c}{n}

Sustituyendo los valores dados:

v=3×108m/s1.33 v = \frac{3 \times 10^8 \, \text{m/s}}{1.33}

Ahora, realizamos la división:

v2.26×108m/s v \approx 2.26 \times 10^8 \, \text{m/s}

Por lo tanto, la velocidad de la luz en el agua es aproximadamente 2.26×108m/s 2.26 \times 10^8 \, \text{m/s} .

This problem has been solved

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