Select all the ordered pairs that are solutions of the equation.(-7, 1)(-1, 7)(0, 5)(2, 3)(3, 2)(5, 0)

To determine which ordered pairs are solutions of the equation, we need to know the equation itself. Since the equation is not provided, let's assume a generic linear equation of the form $y = mx + b$. We will test each ordered pair to see if it satisfies this equation.

1. (-7, 1):

   • Substitute $x = -7$ and $y = 1$ into the equation $y = mx + b$.
   • $1 = m(-7) + b$.

2. (-1, 7):

   • Substitute $x = -1$ and $y = 7$ into the equation $y = mx + b$.
   • $7 = m(-1) + b$.

3. (0, 5):

   • Substitute $x = 0$ and $y = 5$ into the equation $y = mx + b$.
   • $5 = m(0) + b$.
   • $5 = b$.

4. (2, 3):

   • Substitute $x = 2$ and $y = 3$ into the equation $y = mx + b$.
   • $3 = m(2) + b$.

5. (3, 2):

   • Substitute $x = 3$ and $y = 2$ into the equation $y = mx + b$.
   • $2 = m(3) + b$.

6. (5, 0):

   • Substitute $x = 5$ and $y = 0$ into the equation $y = mx + b$.
   • $0 = m(5) + b$.

Since we do not have the specific equation, we cannot definitively determine which pairs are solutions. However, if we assume the equation is $y = -x + 6$ (as an example), we can test each pair:

1. (-7, 1):

   • $1 = -(-7) + 6$
   • $1 = 7 + 6$
   • $1 \neq 13$ (Not a solution)

2. (-1, 7):

   • $7 = -(-1) + 6$
   • $7 = 1 + 6$
   • $7 = 7$ (Solution)

3. (0, 5):

   • $5 = -(0) + 6$
   • $5 = 6$
   • $5 \neq 6$ (Not a solution)

4. (2, 3):

   • $3 = -(2) + 6$
   • $3 = -2 + 6$
   • $3 = 4$ (Not a solution)

5. (3, 2):

   • $2 = -(3) + 6$
   • $2 = -3 + 6$
   • $2 = 3$ (Not a solution)

6. (5, 0):

   • $0 = -(5) + 6$
   • $0 = -5 + 6$
   • $0 = 1$ (Not a solution)

Therefore, based on the assumed equation $y = -x + 6$, the only solution is (-1, 7).

To accurately determine the solutions, the specific equation must be provided.